(4-x)(4+x)=x^2-2

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Solution for (4-x)(4+x)=x^2-2 equation: 


Simplifying
(4 + -1x)(4 + x) = x2 + -2

Multiply (4 + -1x) * (4 + x)
(4(4 + x) + -1x * (4 + x)) = x2 + -2
((4 * 4 + x * 4) + -1x * (4 + x)) = x2 + -2
((16 + 4x) + -1x * (4 + x)) = x2 + -2
(16 + 4x + (4 * -1x + x * -1x)) = x2 + -2
(16 + 4x + (-4x + -1x2)) = x2 + -2

Combine like terms: 4x + -4x = 0
(16 + 0 + -1x2) = x2 + -2
(16 + -1x2) = x2 + -2

Reorder the terms:
16 + -1x2 = -2 + x2

Solving
16 + -1x2 = -2 + x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x2' to each side of the equation.
16 + -1x2 + -1x2 = -2 + x2 + -1x2

Combine like terms: -1x2 + -1x2 = -2x2
16 + -2x2 = -2 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
16 + -2x2 = -2 + 0
16 + -2x2 = -2

Add '-16' to each side of the equation.
16 + -16 + -2x2 = -2 + -16

Combine like terms: 16 + -16 = 0
0 + -2x2 = -2 + -16
-2x2 = -2 + -16

Combine like terms: -2 + -16 = -18
-2x2 = -18

Divide each side by '-2'.
x2 = 9

Simplifying
x2 = 9

Take the square root of each side:
x = {-3, 3}

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